Question

What are the real or imaginary solutions of each polynomial equation?
x^4-29x^2+100

Answer 1

(x^2-29)x^2+100
(x-5)(x-2)(x+2)(x+5)
(x^229/2)^2-441/4

Answer 2

x=-5
x=-2
x=2
x=5

Answer 3

x^4-29x^2+100 = 0
let u=x^2. so your equation can look like this quadratic:
u^2 - 29u +100 = 0

Answer 4

factoring you get (u-25)(u-4) = 0
so u = 25 or u = 4
so x^2 = 25 or x^2 = 4

Answer 5

so x = 5 or -5
x = 2 or -2