Question

A piece of metal is released under water. The volume of the metal is 32.4 cm3 and its specific gravity is 4.5. What is its initial acceleration?

Answer 1

there is an upwad buoyant force equal to weight of water displaced by the metal
=mass(of water displaced)*g
=volume*density of water*g-----1

volume above is volume of water displaced=volume of metal

its own mass*g - 1
gives force on the body divide it by mass of metal to get acceleration

mass of metal=volume*density of METAL