Question

Let f(x)=sin(x)^2-cos(x) on the interval (0,2pi). Where on this interval does f increase and where does it decrease?

Answer 1

remember the trig identity, sin^2 (x)=1-2sin(2x)

Answer 2

make sinx2 as 1-cosx2. then you have quadratic type of equation. differentiate to find graph and monotonic periods...

Answer 3

am i solving for x?

Answer 4

Simplifity it into what apoorvk said, then derive it. after you derive it, solve for x. WHen x is positive, f increases, when x is negative, f decreases.