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How many real number solutions does the following equation have? –8x^2 – 8x – 2 = 0
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There are two real zeros. They are multiples of x=-1/2 So x=-1/2 is a solution.\[(x+1/2)^{2}\]Check \[-8(-1/2)^{2}+-8(-1/2)-2=0\]\[-8(1/4)+4-2=0\]\[-2+4-2=0\]\[0=0\]
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