Question

How do i solve
2(2x)^(1/3) +1=5

Answer 1

subtract 1
divide by 2
cube

Answer 2

2x^1/3=2?

Answer 3

\[2(2x)^{\frac{1}{3}}+1=5\]
\[2(2x)^{\frac{1}{3}}=4\]
\[2(2x)^{\frac{1}{3}}=2\]
\[2x=8\]

Answer 4

damn typo
third line should be
\[(2x)^{\frac{1}{3}}=2\]

Answer 5

how do i handle the exponential 1/3?