Question

please help to find the intergral of Vdv/[g(v^2-2500)]=-the intergral of dx

its a differential equation

Answer 1

let u= v^2-2500
and du = 2 v dv so dv= du/2v

Answer 2

how do i treat g

Answer 3

I assume g is a constant?

Answer 4

I was assuming g was the gravitational constant.

Answer 5

thax

Answer 6

Phi is it proper to put 1/g before the intergral sign

Answer 7

yes