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Mathematics 12 Online
OpenStudy (anonymous):

Is this correct 4x(x-4)-5x(x-3)=0 4x^2-16x-5x^2+15x=0 -x^2-x=0 I got x= -1, 1 as my answer

OpenStudy (anonymous):

no, factor and you'll get -1, 0

OpenStudy (anonymous):

oh, using the quadratic formula right

OpenStudy (anonymous):

you can do that but factoring is way faster...

OpenStudy (anonymous):

oh wait no i see -x^2-x-0

OpenStudy (anonymous):

-x^2-x-0 = 0

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