Question

how to solve this quadratic 143 = (9+2x)(7+2x)

Answer 1

-4x^2-32x+80=0
x=-10
x=2

Answer 2

How did you get negatives when everything in the parenthesis is positive?

Answer 3

first multiply (9+2x) and (7+2x) then subtract 143 from both sides u will get the quadratic equation in standard form, then solve it with quadratic formula.

Answer 4

expand the right hand side

143 = 4x^2 +32x + 63

subtract 143 from both sides

4x^2 + 32x - 80 = 0

factorising

4(x^2 + 8x - 20) = 0

this factorises to

4(x+10)(x -2)=0

x = -10, 2