Question

Find the extreme values of the function and where they occur. g(x)= x^2lnx

Answer 1

first step:get the derivaitve

Answer 2

x[2ln(x)+1]

Answer 3

yes thats the one

Answer 4

now set it equal to zero and solve for x

Answer 5

When I do that, what do I do first to solve for x?

Answer 6

x[2ln(x)+1] =0