Question

what is 1/(secx+1)+1/(secx-1)=???

Answer 1

Simplify?

Answer 2

(1)/(secx+1)+(1)/(secx-1)

(1)/(secx+1) * (secx-1)/(secx-1) + (1)/(secx-1)*(secx+1)/(secx+1)

(secx-1)/((secx-1)(secx+1)) + (secx+1)/((secx-1)(secx+1))

((secx-1)+(secx+1)) / ((secx-1)(secx+1))

2secx / ((secx-1)(secx+1))

2secx/(sec^(2)x-1)

2secx / (tan^(2)x)

2secx / ((sin^(2)x)/(cos^(2)x))

(2secxcos^(2)x) / (sin^(2)x)

2cosx/(sin^(2)x)

2cotx/sinx

Answer 3

\[\frac{\sec x-1+\sec x+1}{\sec ^2x-1}=\frac{2\sec x}{\tan^2x}\]