Question

Find the 9th term of the geometric sequence with a2 = 0.3 and a6 = 0.00003

Answer 1

an = a1r^n-1
(((0.3r)r)r) = 0.00003
0.3r^3 = 0.00003
r^3 = 0.0001
r = 0.0464158883

so a1 = 6.46330408

so a9 = (6.46330408)(0.0464158883)^8
a9 = 1.39 × 10^-10