Question

Find a pair of factors for each number by using the difference of two squares.
a. 45
b. 77
c. 112

Answer 1

45=49-4=(7+2)(7-2)= 9 x 5
77= 81-4= (9+2)(9-2)= 11x 7
112= 121-9= (11+3)(11-3)= 14 x 8

Answer 2

1. (d-7)(d-7) or (d-7)^2
2. (r-7)(r+7)
3. (7b+5)(7b+5) or (7b+5)^2

4. 10u^3 + 4u^2 - 2u + 10

For number 5, I don't quite understand what its asking for ...
Do you mean like:

a. 45 = (7-2)(7+2)
b. 77 = (9-2)(9+2)
c. 112 = (11-3)(11+3)