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If OB = 10 and RB = 8, then OR = ?
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oh.
that's it?
oh wait...they're not colinear
how do I solve?
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pythagorean theorem
sorry I can't help u on this one buddy I'm confuzled
10^2 = 8^2 + b^2 b^2 = 100 - 64 b = sqrt (36) b = 6
Oh! okay. Thank you.
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