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Let f(x) = x – 3 and g(x) = x + 11. Find f(x) • g(x). x2 – 8x – 33 x2 – 8x + 14 x2 + 8x + 14 x2 + 8x – 33
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\[f(x) \cdot g(x)=(x-3)(x+11)\] Just expand and simplify
so it would be x2-8x+14 where does the 8x come from?
Nope. -3(11) is not 14
Also 11x-3x is not -8x
\[(x-3)(x+11)=x(x+11)-3(x+11)=x \cdot x + x \cdot 11 -3 \cdot x -3 \cdot 11\]
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f(x).g(x)= (x-3)(x+11) =x(x+11)-3(x+11) =x2+11x-3x-33 =x2+8x-33
awesome thanks i understand
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