Im stuck here.

Factor

2x^5-6x^4+8x^3
i get
2x^3(x^2-3x+4)
They want complete factorization but i dont know what to factor it into

Question

Im stuck here. 

Factor

2x^5-6x^4+8x^3
i get
2x^3(x^2-3x+4)
They want complete factorization but i dont know what to factor it into

directrix · Answer

2x^5-6x^4+8x^3

= 2x^3(x^2-3x+4)
----------------
^^ brc's work

Why do you think there's more factoring to do?

anonymous · Answer

it just asks for complete factorization, just seemed like there should be one more step

anonymous · Answer

but since we cant factor past that that is complete then

directrix · Answer

Can you think of two numbers that multiply to 4 and add to -3 ?

anonymous · Answer

haha no. That is the part where i got stuck and felt like there should be more.

directrix · Answer

There are prime polynomials just as there are prime numbers.

anonymous · Answer

Much thanks man. Have been hitting homework hard this week to get ahead. Brain is fried lol

directrix · Answer

It seems to me that your brain is working.

anonymous · Answer

Yea just overthinking it