Thrown Horizontally from Height with initial Velocity Vo.... initial condition y(t=0)=0, x(t=0)=0,
the equations of motion is:dx/dt=Vo, dy/dt=0;d^2x/dt^2=0;d^2y/dt^2=-g
Vx(t)=dx/dt= Vo; Vy(t)=dy/dt=-gt.... x(t)=Vot; and y(t)= -1/2 gt^2
a) What is the maximum height reached by the object?
b) How long the object stays in the air?
c) How far from its initial location the object hits the ground?
d) With what velocity does the object hits the ground?

Question

Thrown Horizontally from Height with initial Velocity Vo.... initial condition y(t=0)=0, x(t=0)=0,
the equations of motion is:dx/dt=Vo, dy/dt=0;d^2x/dt^2=0;d^2y/dt^2=-g
Vx(t)=dx/dt= Vo; Vy(t)=dy/dt=-gt....  x(t)=Vot; and y(t)= -1/2 gt^2
a)	What is the maximum height reached by the object?
b)	How long the object stays in the air?
c)	How far from its initial location the object hits the ground?
d)	With what velocity does the object hits the ground?

shayaan_mustafa · Answer

hello sadaf :)

Sorry to say.. but this question is not able to understand. write it in easiest way.
Thank you.