Question

find an equation for the line tangent to y= 4-6x^2 at (5,-146)

Answer 1

differentiate to find dy/dx which gives value of slope 'm' at any particular(x",y"), which is given. now the tangent also passes through (x",y"). so write an equation for the line with slope m passing through (x",y") as:
(y-y")=m(x-x")

Answer 2

do you have the answer ?

Answer 3

what did you get? post and verify...

Answer 4

yeah i have my answer.. now you say what you got??

Answer 5

i got Y=90x+103

Answer 6

right

Answer 7

nope.. it should be
y+60x=154

Answer 8

dont worry buddy, keep trying!

Answer 9

no its not like what you thing
its actually y= -90x+228

Answer 10

you sure?? lemme recheck