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What value is added to both sides of the equation x2 – 6x = 10 in order to solve by completing the square?
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\[x^2-6x=10 ?\]
yess !
the answer is decimal, take a litle longer to solve
\[(x-3)^2=10+3^2\]\[x-3=\pm \sqrt{19}\]\[x=3\pm \sqrt{19}\]
\[\frac{6}{2}=3,3^2=9\]
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there are a nother way to solve
\[x^2-3x +9=10+9\]
Add 9 to both sides to complete the square.
\[x^2-6x+9=10+9\]
\[(x-3)^2=19\]
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yes,2 way can solve I like the frist way I solve it short cut and faster
\[x-3=\pm \sqrt{19}\]
\[x=3\pm \sqrt{19}\]
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