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if f(x)=3x^2-2x+1 and f(g(x))=12x^2-16x+6 now g(x)=?
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f(g)(x)=2(6x^2-8x+3)
12x^2+6=f(g)(x)+16x
no no f(x)=false!!!
f(g(x))
f(g)(x)=false!!
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may you solve it?
12x^2-16x+6 = 12x^2 - 12x +3 -4x +2 +1 = 3(4x^2 -4x+1) - 2(2x-1) +1 = 3(2x-1)^2 - 2(2x-1) +1 so g(x)= 2x-1
oh yeah thanks
my pleasure XD
Nicely done hoblos! 100 medals for you :D
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thanks ffm :D
I don't know why I was thinking so much complicated :P KISS works here too :D
KISS: keep it simple silly :P
lol
foolformath! Give me a kiss?
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