Question

compose an equation for the tangent line in the point (-1,1) for the curve with cartesian equation (x^2+y^2)^3=8x^2y^2 ?
partial derivates are:
6 x (x^2 + y^2)^2 == 16 x y^2 and
6 y (x^2 + y^2)^2 == 16 x^2 y
but at this point im lost... tx

Answer 1

use implicit differentiation, put the values, find the slope, and you know the point, so find the equation of tangent