Question

use implicit differentiation to find the slope of the tangent line at (-2,3) and use it to find the equation of the tangent line in y=mx + b form

x^2+y^2=13

Answer 1

differentiate it

2x+2y*dy/dx = 0; or dy/dx = -x/y

put the value m = 2/3

since you know point, find the equation

Answer 2

ok ya thats what i got for the slope but i don't know how to find b

Answer 3

put the values -2, 3 on that equation and value of slope, you will find b

Answer 4

ok
well i got y=2/3x+5/3 but thats not right either..

Answer 5

b = 3 + 2*4/3

Answer 6

sorry, 3+2*2/3