Question

what is the solution to this system
y = x² + 3x – 4
y = 2x + 2

Answer 1

what is the solution to this system
y = x² + 3x – 4 = Y=x^2+3x-4

Answer 2

y = 2x + 2 =y=2(x+1)

Answer 3

Set y = y

x^2 + 3x - 4 = 2x + 2

Then solve for x

Answer 4

how do I solve for x?

Answer 5

subtract 2x+2 from both sides to get

x^2 + x - 2 = 0

Then factor by grouping:

x^2 + 2x - x - 2 = 0
x(x+2)-1(x+2) = 0
(x+2)(x-1) = 0
x = -2,1