write an equation in slope intercept form for the line that is parallel to the given line and that passes through the given point: 4y=x;(4,0)

Question

anonymous · Answer

1.  Find the slope of the current line:
4y=x
first re-write the equation:
y = x/4
compare with general line equation:
y = mx + c,  where m is the slope
so current line:
y = x/4  => slope is 1/4
A line perpendicular to this will have a slope of  -4/1

therefore the equation = y = -4x + c
now plug in the point above (4,0)
=> 0 =-4*4 +c
=> 16 =c

Therefore the equation of the new line is:

y=-4x +16

anonymous · Answer

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