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The sum of the digits of a two-digit number is seven. When the digits are reversed, the original number is increased by nine. Find the number
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okay let one's place digit be x and ten's place digit be y then the no. is 10y+x so, x+y=7 ....(i) after reversal the no. becomes 10x+y acc. to what's given, 10x+y=10y+x+9 simplifying, or, 9x-9y=9 or, x-y=1 ....(ii) solve equations (i) and (ii) to get x and y.
then ofcourse 10y+x is the no.!!
34
Pikman. it helps if you dont just feed answers and can give an explanation :))
if he needs an explanation then he would ask
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Yes true
ofcourse we arent just gonna feed answers. we give answers if asked not explnations! the concept is important my boy!! :)
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