Question

try this one...

Answer 1

\[\sqrt{3+\sqrt{3+\sqrt{3+\sqrt{3+...}}}}\]

Answer 2

evaluate...

Answer 3

say, the term is x
so, x^2=3+x
solve for x, take the positive solution..

Answer 4

exact value???

Answer 5

\[[1+\sqrt{13}]/2\]

Answer 6

ok... @Arnab09 got it...

Answer 7

let x = that
x^2 = 3 + sqrt (3 + sqrt 3 + sqrt 3 +...))))
x^2 = 3 + x
x^2 - x - 3 = 0

-(-1)+/- sqrt(-1^2 - 4(1)(-3)/2(1)

1 +/- sqrt (1 + 12)/2

(1 +/- sqrt 13)/2

x = 2.303

Answer 8

continued fractions anyone???