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81b^2-121
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I guess you want factor, so i put some factor in your factoring question :D The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b). (9b-11)(9b+11)
(9b)^2 - (11)^2 use a^2-b^2 formula
yes i wanted to factor completely
(9b-11)(9b+11)
find numbers for which rational expressions can be unidentified
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q^3-4q/q^2-4
\[q^3-4q \over q^2-4\]
I'm new to this I'm sorry
\[\sqrt{7x+46}= x+4\]
\[\sqrt[3]{23}\]
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