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solve for x to eight decimal placed if e^(2x-7)=252. Base E is a physical constant.
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\[2x-7=\ln 252\] \[x=\frac{\ln 252+7}{2}\]
e^(2x-7) = 252 ln(e^(2x-7)) = ln(252) (2x-7)ln(e) = ln(252) (2x-7)*1 = ln(252) 2x-7 = ln(252) 2x = ln(252)+7 x = ( ln(252)+7 )/2 x = 6.26471454
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