Question

Find the derivative of:
y=e^sec-1x (inverse trig functions)

Answer 1

\[y = e^{\sec^{-1}(x)} \]

Answer 2

yea thats how it looks.

Answer 3

\[{e^{\sec^{-1}(x)}} \over {\sqrt{1-{1\over x^2}} \ x^2}\]

Answer 4

http://www.wolframalpha.com/input/?i=deriv%28e%5EarcSec%28x%29%2C+x%29

Answer 5

thanks so much. this really helped! :)

Answer 6

You're welcome :)