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OpenStudy (anonymous):
complicated calculus problem: derivative of g(x) = (2ra^(rx)+n)^p ?
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OpenStudy (anonymous):
the textbook answer is g'(x) = 2r^(2) p (ln a) (2ra^(rx) + n)^(p-1) a^(rx) i can get pretty close but don't know where the hell the exponent 2 comes from
OpenStudy (anonymous):
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