Question

Evaluate the integral using integration by parts where possible:
(x)/((x-9)^2)dx

Answer 1

why parts? partial fraction or u-sub will get it right away

Answer 2

hey satellite i was wondering if you could help me after?

Answer 3

let me try that again
\[u=x+9, du = dx, x=u+9\]
\[\int\frac{u+9}{u^2}du=\int \frac{1}{u}du+\int\frac{9}{u^2}du\]
\[\ln(u)-\frac{9}{u}\]
\[\ln(x-9)-\frac{9}{(x-9)}\]