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Solve the quadratic equation. x^2 - 4x - 3 = 0
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(x-4)x=3 x^2=4x+3 (x-2)^2-7=0 x=2 x=2
kumar that is wrong.
How is that wrong
since you cant factor that trinomial, youll have to plug it into the quadratic equation.
I think I am right.
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the answer is 2\[\pm \sqrt{7}\]
2 plus/minus root 7
x=2+ sqroot 7
which one should i pick??? (A) 2+- sq rt 7 (B) 4+-2 SQ RT 7 (c) 2+- sq rt 7 over 2 (D) 2+- SQ RT 28 OVER 2
A.
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kumar, anytime you take the square root of both sides of the equation the answer will be +/-.
thax
sq rt x-3 then outside the sq rt box is +6=2
\[\sqrt{x-3} +6=2\]
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