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multiply (3x-4)(6x+7)
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(3x-4)(6x+7)
18x^2-3x-28 x(18x-3)-28 1/8(12x-1)^2-225/8 x=-7/6 x=4/3
Distribute the terms (3x-4) * (6x+7) = (3x * 6x) + (3x * 7) + (-4 * 6x) + (-4 * 7) = 18x^2 + 21x -24x -28 = 18x^2 -3x -28
Thanks!
no problem. i think kumar set the equation equal to 0, which you don't need unless it tells you to do that. just make sure you know what you're doing for when a test comes
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