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OpenStudy (anonymous):
integrate (e^x)/(square root(e^x+1)) dx
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OpenStudy (anonymous):
use the u-substitution .
OpenStudy (anonymous):
make u=e^x+1 du=e^x dx
OpenStudy (anonymous):
so you have integral of sqaure root of u. and hten integrate that. 2/3 (e^x+1)^3/2
OpenStudy (anonymous):
get it?
OpenStudy (anonymous):
|dw:1332733514048:dw|
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