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Mathematics 10 Online
OpenStudy (anonymous):

HELP PLEASE!! A particle moves along the curve given by y=the square root of(x^3+1). Find the velocity at 2secs.

OpenStudy (anonymous):

Is x representing time? If so, you can just differentiate and plug 2 into the derivative y'.

OpenStudy (anonymous):

You need to derive you position equation y=sqrt{x^3+1)

OpenStudy (anonymous):

ok thanks!! Can you all check my last question also please?

OpenStudy (anonymous):

Sure :)

OpenStudy (anonymous):

yes not even 10 minutes ago.

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