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OpenStudy (anonymous):
HELP PLEASE!! A particle moves along the curve given by y=the square root of(x^3+1). Find the velocity at 2secs.
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OpenStudy (anonymous):
Is x representing time? If so, you can just differentiate and plug 2 into the derivative y'.
OpenStudy (anonymous):
You need to derive you position equation y=sqrt{x^3+1)
OpenStudy (anonymous):
ok thanks!! Can you all check my last question also please?
OpenStudy (anonymous):
Sure :)
OpenStudy (anonymous):
yes not even 10 minutes ago.
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