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Solve for x: 2-ln x = 2x^(3/2) This is where I got stuck 2 = 2x^(3/2) + ln x 2-2x^(3/2) = ln x e^(2-2x^(3/2))=x
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there isn't a way to isolate x algebraically but you can solve it numerically http://www.wolframalpha.com/input/?i=2-ln%28x%29+%3D+2x^%283%2F2%29
thanks dumbcow!
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