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find the perfect square of x^2-4-2=0
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x^2-4x-2=0
The pattern you are trying to match is\[x^2-2ax+a^2=(x-a)^2\]
How do i start the problem out?
Look at the pattern I gave you , and the pattern of the problem. Can you find a value of a to plug into my pattern that will give your equation?
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