Question

Which is the extraneous solution of

Answer 1

–5
–3
3
5

Answer 2

x^2-2x-15=0
x^2-5x+3x-15=0
x(x-5)+3(x-5)=0
(x+3)(x-5)=0
x=-3,5
what do you mean by "Extraneous Solutions"

Answer 3

i dont know thats what the question asked. :/

Answer 4

There is only one solution for that equation.

Answer 5

You have to discard the x=5.

Answer 6

so the answer is -3?

Answer 7

You can plug the -3 value into the equation and you'll check it by yourself

Answer 8

how do i do that? :/