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Mathematics 16 Online
OpenStudy (anonymous):

Which is the extraneous solution of

OpenStudy (anonymous):

OpenStudy (anonymous):

–5 –3 3 5

OpenStudy (anonymous):

x^2 = 2x + 15 = x^2 - 2x - 15 = (x - 5) . (x+3) thus x = 5 or -3

Directrix (directrix):

Solution is x = -3 so x = 5 is the extraneous root.

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