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set up equations x+w=20 A= 2x^2+w or A= 2x^2 -x +20
find the min of the parabola
\[f(x)=(2x)(20)-(2x-1)(20-x),\]\[f'(x)=4x-1\implies4x-1=0\implies x=\frac{1}{4}.\]I am not sure if this is correct, though.
thanks :]
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