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OpenStudy (anonymous):
7/2x-3 + 3/2x+3 please ?
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OpenStudy (anonymous):
what is it your looking for?
OpenStudy (anonymous):
are you just solving for x
OpenStudy (anonymous):
no I'm adding fractions with a variable
OpenStudy (anonymous):
7(2x+3)+3(2x-3)/(2x-3)(2x+3)--> SOlve it..
OpenStudy (anonymous):
ok well your answer should be 5x
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OpenStudy (anonymous):
ok can someone explain to me how that's the answer? since my answer is supposed to be in fraction form with a common denominator
OpenStudy (anonymous):
20x-12/4x^2-9
OpenStudy (anonymous):
(20x-12)/(4x^2-9)....you get this by cross multiplying..multiply the left fraction by 2x+3 and the right fraction by 2x-3 and multiply out
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