Mathematics
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OpenStudy (anonymous):
use the echelon method to solve system of equalities
X+y=10
5x-y=44
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OpenStudy (shayaan_mustafa):
hello tishagwen. are you there?
OpenStudy (shayaan_mustafa):
hello mr.
OpenStudy (anonymous):
sorry yea im here
OpenStudy (anonymous):
and its mrs.. ")
OpenStudy (shayaan_mustafa):
oh .. hehehehhehe... mrs. or right. let us solve it.
Well I don't know how to use arrays on this site. so kindly. try to understand me.
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OpenStudy (anonymous):
the problem changed sorry
OpenStudy (shayaan_mustafa):
yes. what is it?
OpenStudy (anonymous):
X+y=10 5x-y=44
OpenStudy (shayaan_mustafa):
miss it is the same question that you've posted.
OpenStudy (anonymous):
if i understand right.. ill need to take the first set and multiply by 5 and the the 2nd one multiply by-1 right?
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OpenStudy (shayaan_mustafa):
no no. here you are solving the equation with Gauss elimination method(Echelon form).
OpenStudy (anonymous):
oh ok
OpenStudy (shayaan_mustafa):
so first write equation as matrices form.
1 1 10
5 -1 44
OK?
OpenStudy (anonymous):
got it
OpenStudy (shayaan_mustafa):
ok now
Replace row 2 (i.e. R2) with the row operation R2 new=-4*R1+R2 in order to convert some elements in the row into the desired value 0.
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OpenStudy (shayaan_mustafa):
do this step. then tell me.
OpenStudy (anonymous):
x-5y=-34
OpenStudy (shayaan_mustafa):
no no my dear.
OpenStudy (shayaan_mustafa):
do the row operation on R2(row 2)
OpenStudy (anonymous):
what do you mean
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OpenStudy (shayaan_mustafa):
means. multiply R1 with 4 and minus it from R2 i.e. R2new=R2-4R1
Does this make sense to you?
OpenStudy (anonymous):
not really
i know nothing of the matrix stuff
OpenStudy (shayaan_mustafa):
now look at pic and here I am going to solve it for you. keep the pic in mind. OK
OpenStudy (anonymous):
how did u get 4 i thought it was 5
OpenStudy (shayaan_mustafa):
yes yes it is 5 sorry. it is a mistake.
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OpenStudy (anonymous):
ok
OpenStudy (shayaan_mustafa):
step#2) multiply R1 with 5|dw:1332792360847:dw|