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solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 + 7x = –12 (1 point) 3, –4 –3, –4 3, 4 –3, 4
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x^2 + 7x = –12
well you know the two x are 3 and 4. since both 7 and 12 have + , you know that 3 and 4 are also positive
x=4; -3
\[x ^{2}+4x+3x+12\] x(x+4)+3(x+4) x+4=0; x+3=0 x=-4; -3
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