Question

Solve for x:

Answer 1

Multiply all terms by the common denominator which is 21x(x+4)

Answer 2

Remember that x cannot be 0 or -4

Answer 3

then no solution

Answer 4

I got x = 3

Answer 5

lest's satrt with the left hand side
L.H.S=(3x+12+3x)/(3x^2+12x)
then we multiply l.h.s with r.h.s to get
21x^2+84x+21x^2=30x^2+120x
therefore
42x^2+84x=30x^2+120x
so
12x^2=36x ................ therefore........... 12x^2-36x=0
so.... 12x(x-3)=0
therfore (X=0) Refused.............or........... x=3

Answer 6

\[21x(x+4)\times\frac{3}{3x}+21x(x+4)\times\frac{1}{x+4}=\frac{10}{7x}\times \times21x(x+4)\]

Answer 7

\[7(x+4)(3)+21x(1)=10(3)(x+4)\]

Answer 8

\[21x+84+21x=30x+120\]

Answer 9

\[42x+84=30x=120\]

Answer 10

\[12x=36\]

Answer 11

\[x=3\]