Question

x^2- 6x=7x + 48

Answer 1

(x+3)(x-16) = 0
then x = -3 and x = 16

Answer 2

1st - minus both sides by 7x
we have: x^2 - 6x - 7x = 7x - 7x + 48
-> x^2 - 13x = 0 + 48
2nd - minus both sides by 48
we have: x^2 - 13x - 48 = 48 - 48
-> x^2 - 13x - 48 = 0
now we can guess that 16*3 = 48 and 3 - 16 = -13
so we group them together as:
(x+3)(x-16) = 0
to make sure, you can multiplay them together:
x*x + x*(-16) + 3*x + 3*(-16) = x^2 -16x + 3x - 48
= x^2 - 13x - 48 (as we expect the simplified shoul be)
so we have (x+3)(x-16)=0
therefore, x=-3 and x=16
plug back in (-3+3)(-3-16)=0 because -3+3 =0 and everything times 0 = 0
the same with x = 16

Answer 3

Got it. Thanks so much to you!