Question

Find the equation, in slope-intercept form, for the line perpendicular to the given line and passing through the indicated point.

Answer 1

Perpendicular to 2(y+x)-3(x-y)=-9 and passing through (2,5)

Answer 2

Ok, first we need the slope of this given line, m1. The line perpendicular to the given line will have a slope m2, where m1m2=-1
expanding the above:
2y+2x-3x+3y=-9
5y=x-9
y=(1/5)-(9/5)
Okay so m1=1/5
Thus (1/5)m2=-1
m2=-5
We need a line with slope=-5 through (2,5).
y-5=-5(x-2)
y-5=-5x+10
y=-5x+15

Answer 3

Wow good job!

Answer 4

ty :)

Answer 5

Welcome :)