Question

if a+b+c=2, what does -8c-8a-8b equal???

Answer 1

take -8 common an put value of a+b+c

Answer 2

hint
\[-8(a+b+c)=?\]

Answer 3

oh ok -16

Answer 4

how did you know to do that????? I have been trying to rearrange a+b+c=2 to find the value of the variables and then plug those in

Answer 5

\[-8c-8a-8b \] by the distributive property this is
\[-8(c+a+b)=-8(a+b+c)\]

Answer 6

since
\[a+b+c=2\] you know
\[-8(a+b+c)=-8\times 2=-16\]

Answer 7

brilliant