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Find the angle for which a projectile fired from a height h with velicity u at an angle theta will have max. range
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0 of course ... to have max range you need to have max horizontal component ... vertical component to initial velocity will only make fall faster
0 is wrong. Give me a minute to elaborate.
what do you mean ... when fired from HEIGHT???
It is fired for a height h upward with an angle theta
than that would be 45
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Yeah and now we are firing from a height h
it would be different because the y component would be zero later than when fired from ground
Didn't see it was launched from a different height.
Yeah that's what makes the difference
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