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OpenStudy (anonymous):
In △DEF, what is the length of line segment DF?
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OpenStudy (anonymous):
OpenStudy (aroub):
In 30-60-90 triangle: the longer leg= sqrt3 times the shorter leg DE=sqrt3(FE) 45=sqrt3(Fe) FE= 45/sqrt3 FE=15sqrt3 & the hypotenuse= 2 times the shorter leg FD=2(15 sqrt3) FD=30sqrt3
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