Question

What is the total number of points equidistant from two intersecting lines and 2 centimeters from the point of intersection ?

A.1
B. 2
C. 3
D. 4
E. 0

Answer 1

It is four.

First part, the points equidistant from the two intersecting lines. Think of them as making an X. A line drawn across the X and another up and down the X, like laying a + sign on it, are made up of points which are all equidistant from the two lines.

Then the part about being 2cm from the point of intersection. As if you haven't overlayed enough lines already (!), draw a circle with a radius of 2cm and centered on the point of intersection. Those are all the points that are 2cm from the point of intersection.

The four places that circle and the lines of the "+" intersect are the four points satisfying the conditions.