4. A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?
35 feet
40 feet
42 feet
45 feet

Question

4.   A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?
35 feet
40 feet
42 feet
45 feet

anonymous · Answer

substitute the t in the equation for a 3, and work from there

anonymous · Answer

so whats the answer

anonymous · Answer

h(t) = -16t^2 + 60t + 6

At t=3 we find h(3):
h(3) = -16(3)^2 + 60(3) + 6
       = -16(9) + 180 + 6
       = 42 ft

C.

anonymous · Answer

thanks